简单的模拟题
只要按公式计算F1 = 2 * precision * recall / (precision + recall)
即可
简单的模拟题
只要按公式计算F1 = 2 * precision * recall / (precision + recall)
即可
#include <iostream>
#include <cstdio>
#define LL long long
#define rg register
using namespace std;
template<class T>
inline void read(T &x)
{
x=0;
bool f=0;
char c=getchar();
for(;!isdigit(c);c=getchar())
f^=c=='-';
for(;isdigit(c);c=getchar())
x=x*10+(c^48);
x=f?-x:x;
}
int precision,recall;
double ans;
int main()
{
read(precision),read(recall);
ans=2*precision*recall/(precision+recall);
printf("F1 = %f",ans);
}
using namespace std; int main(void){ double F1; int precision,recall; cin>>precision>>recall; F1= 2*precision*recall/(precision+recall); cout<
#include<stdio.h>
int main() {
scanf("%d %d", &precision, &recall);
printf("F1=%d", 2 * precision * recall / (precision + recall));
return 0;
}
void main(){long double F1;int precison;int recall;printf("F1=%d",2*precison*recall/(precision+recall))}
using namespace std int main() { long double F1; int precision; int recall; F1=2*precision*recall/(precision+recall); count<